Ngā Pūrongo - Kia pēhea te roa o te wā e utua ai te pākahiko o te motopaika?

Kia pēhea te roa o te wā e utua ai te pākahiko o te motopaika?

Kia pēhea te roa o te utu i te pākahiko o te motopaika?

Momo Pūhiko	Ngā Whakakaha Tautuhi	Te Wā Utu Toharite	Ngā Tuhipoka
Waikawa-Mata (Waipuke)	1–2A	8–12 hāora	Ko te mea tino noa i roto i ngā pahikara tawhito
AGM (Whāriki Karāhe Mimihia)	1–2A	6–10 hāora	He tere ake te utu, kāore he tiaki
Pūtau Kiri	0.5–1A	10–14 hāora	Me whakamahi i tētahi rihi iti-amperage
Ritiumu (LiFePO₄)	2–4A	1–4 hāora	Ka tere te utu engari me whai rihi hototahi

Te kaha o te pākahiko (Ah)
– E rua te roa o te utunga o te pākahiko 12Ah i te pākahiko 6Ah e whakamahi ana i te rihi kotahi.
Putanga Tauira (Amps)
– Ka tere ake te utu o ngā rihi hiko teitei ake, engari me ōrite ki te momo pākahiko.
Āhua o te Pūhiko
– Tērā pea ka roa ake te utu mō te pākahiko kua tino mimiti te wai, kua whai whanariki rānei, kāore rānei e utu tika.
Momo Utauta
– Ka whakarerekētia e ngā rihi atamai te putanga, ā, ka huri aunoa ki te aratau tiaki ina kī ana.
– He puhoi te mahi a ngā rihi maturuturu engari he haumaru mō te whakamahinga roa.

$Wā Utu (hāora)=Pūhiko AhWhakakaha Utu × 1.2\text{Wā Utu (hāora)} = \frac{\text{Pūhiko Ah}}{\text{Whakakaha Utu}} \times 1.2$

Wā Utu (hāora)=Ampere UtuPūhiko Ah×1.2

Tauira:
Mō te pākahiko 10Ah e whakamahi ana i te rihi 2A:

$102×1.2=6 hāora\frac{10}{2} \times 1.2 = 6 \text{ hāora}$

210×1.2=6 hāora

Kaua e utu nui rawaIna koa mō ngā pākahiko waikawa-mata me te pākahiko tiēre.
Whakamahia he Utauta AtamaiKa huri ki te aratau mānu ina utua katoatia.
Āraia ngā Utauta TereKa kino pea te pākahiko mēnā ka tere rawa te utu.
Tirohia te NgaohikoMe pānui te pākahiko 12V kua kī katoatia12.6–13.2V(Tērā pea ka teitei ake te AGM/litium).